markdown沙盒

weakish
  • 24.3k

大家可以在这里实验Markdown的各种语法。

markdown 沙盒
我们的目标是 把SegmentFault玩坏~

                                        
                                                                
                                                                
                                                                

no-highlight (x) -> x + 1

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小塔楼
                                                  
                                                  
                                                  
                                        
                                        
                                        
                                        
                                        
                                        
                                        
                                        
                                                                
                                                                
                                       
                                       
                                       
                                        
                                        
                                                
                                                
                                                

占位测试测试


栏数较多的表格

Software Maintainer Development status Repository model Concurrency model License Platforms supported Cost
AccuRev SCM AccuRev, Inc. actively developed Client–server Merge or lock Proprietary Most Java Platforms (Unix-like, Windows, OS X) Non-free Quoted on an individual basis.
GNU Bazaar Canonical Ltd. actively developed Distributed[nb 1] Merge GNU GPL Unix-like, Windows, OS X Free
BitKeeper BitMover Inc. actively developed Distributed Merge Proprietary Unix-like, Windows, OS X Non-free Quoted on an individual basis.
CA Software Change Manager CA Technologies[1] actively developed Client-server Merge or Lock Proprietary Unix, Linux, Windows, i5/OS Non-free Named licenses available with volume discounts available
ClearCase IBM Rational actively developed Client–server Merge or lock[nb 2] Proprietary Linux, Windows, AIX, Solaris, HP UX, i5/OS, OS/390, z/OS, Non-free $4600 per floating license (held automatically for 30-minutes minimum per user, can be surrendered manually)
Code Co-op Reliable Software actively developed Distributed Merge Proprietary Windows Non-free $150 per seat
Codeville Ross Cohen official site offline; latest release July 13, 2007 (2007-07-13) Distributed precise codeville merge BSD Unix-like, Windows, OS X Free
CVS The CVS Team[2] maintained but new features not added Client–server Merge GNU GPL Unix-like, Windows, OS X Free
CVSNT March Hare Software[3] and community members maintained and new features under development Client–server Merge or lock GPL or proprietary Unix-like, Windows, OS X, i5/OS Free (with £425 distribution fee) for older version or £85 commercial license for latest version of CVS Suite or Change Management Server
darcs The Darcs team actively developed Distributed Merge GNU GPL Unix-like, Windows, OS X Free
Fossil D. Richard Hipp actively developed Distributed Merge BSD POSIX, Windows, OS X, Other Free
Git Junio Hamano actively developed Distributed Merge GNU GPL POSIX, Windows, OS X Free

objective-c

objectivec正常

-(void)animationFrame
{
    [UIView beginAnimations:nil context:NULL];
    [UIView setAnimationDuration:5];
    [UIView setAnimationCurve:UIViewAnimationCurveEaseOut];// 动画相对速度,开始和结束的时候慢,中间快
    view.center = CGPointMake(0,0);
    [UIView commitAnimations];
}

objective-c不正常

```objective-c

-(void)animationAlpha
{
[UIView beginAnimations:nil context:NULL];// 需要设置代理时
[UIView setAnimationDuration:1];// 动画的持续时间
[UIview setAnimationDelay:1];// 动画延迟时间
view2.apleha = 0.0;
[UIView commitAnimations];// 标记着动画块的结束
}


不加关键字自动判断正常


https://gist.github.com/8322802

http://jsfiddle.net/7g5JP/

今天的 markdown 里的 code 似乎不会换行了?

def say_yes!
    puts "Yes!"
end

最近在写光线跟踪程序,想实现一个n-Rook采样器。原理是是先在一个单位正方形的对角线上放置n个点,然后随机的将这n个点的x坐标打乱,从而保证:

  1. n个点均匀的分布在单位正方形上
  2. 如果将正方形分成n*n个小正方形,那么每个大正方形的每行每列都只有一个元素。

现在,我用C++将上面的思想实现出来,得出的结果是这样的
完美洗牌算法是参照Matrix87大神的文章实现的http://www.matrix67.com/blog/archives/879

主要的代码有:

NRook::NRook(int num) :Sampler(num)
{
    for (int i = 0; i < num; i++)
    {
        sampleList[i].x = 1.f*(i) / numSample;
        sampleList[i].y = 1.f*(i) / numSample;
    }
}

void NRook::shuffle()
{
    for (int i = 0; i < numSample; i++)
    {
        int targetX = randomGen.getRandomI(i, numSample);
        std::swap(sampleList[i].x, sampleList[targetX].x);
    }
}

struct RandomGen{
    virtual float getRandomF(){
        return static_cast <float>(rand()) / static_cast <float>(RAND_MAX);
    }
    virtual float getRandomF(float a, float b) { return (b - a)*getRandomF() + a; }
    virtual int getRandomI(){ return rand(); };
    virtual int getRandomI(int a, int b){ return a + getRandomI() % (b - a); }
};

请问这是选择算法的问题还是实现的问题

如果用3反撇号(backtick)做的代码,似乎换行有问题:

<?php
phpinfo();

用4空格缩进做的代码似乎就没事

<?php
phpinfo();

作为3反撇号的惯用者表示(╯°口°)╯(┴—┴!!!

成功者
  • 3
新手上路,请多包涵

小塔楼

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