照着JsDOM编程艺术码了实例，关于ajax,为什么会出错

Question

照着JsDOM编程艺术码了实例，关于ajax,为什么会出错

发布于
2016-06-03

       
  html：     
   
       <!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8"/>
    <title>Ajax</title>
</head>
<body>
    <div id="new"></div>
    <script type="text/javascript" src="addLoadEvent.js"></script>
    <script type="text/javascript" src="getHTTPObject.js"></script>
    <script type="text/javascript" src="getNewContent.js"></script>
</body>
</html>
   
   
   以下是js： 
    
    检查兼容性：
    function getHTTPObject(){
        if(typeof XMLHttpRequest =="undefined")
            XMLHttpRequest = function (){
                try {return new ActiveXObject("Msxml2.XMLHTTP.6.0");}
                catch (e) {} 
                try {return new ActiveXObject("Msxml2.XMLHTTP.3.0");}
                catch(e){}
                try {return new ActiveXObject("Msxml2.XMLHTTP");}
                catch(e){}
                return false;
            }
            return new XMLHttpRequest();
    }
    
    
    
    指定发送请求：
    function getNewContent(){
    var request =getHTTPObject;
    if(request){
        request.open("GET","example.txt",true);
        request.onreadystatechange = function(){
            if(request.readyState ==4){
                var para = document.createElement("p");
                var txt = document.createTextNode(request.responseText);
                para.appendChild(txt);
                document.getElementById('new').appendChild(para);
            }
        };
        request.send(null);
    }else{
        alert('Sorry.')
    }

}

addLoadEvent(getNewContent);

用浏览器打开显示错误：

getNewContent.js:4 Uncaught TypeError: request.open is not a function

为什么？？

ajax

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1 个回答

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hsfzxjy

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发布于
2016-06-03