如何把数组对象相同的key值合并,并且把对应的id放到一个数组

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  • 46

例如旧数据:
var old = [

{
    id: 1,
    name: 'css',
    type: 'html'
},
{
    id: 2,
    name: 'css',
    type: 'html'
},
 {
    id: 3,
    name: 'javacript',
    type: 'code'
},
{
    id: 4,
    name: 'javacript',
    type: 'code'
}

]
想得到的 var new = [

{
    id: [1,2],
    name: 'css',
    type: 'html'
},
 {
    id: [3,4],
    name: 'javacript',
    type: 'code'
},

]
希望把相同name的对象合并,并且把对应的id放到一个数组

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2 个回答
✓ 已被采纳
var hash = {};
var i = 0;
var res = [];
old.forEach(function(item) {
    var name = item.name;
    hash[name] ? res[hash[name] - 1].id.push(item.id) : hash[name] = ++i && res.push({
        id: [item.id],
        name: name,
        type: item.type
    })

});
console.log(JSON.stringify(res))

从下面的数组 old

var old = [
    {
        id: 1,
        name: 'css',
        type: 'html'
    },
    {
        id: 2,
        name: 'css',
        type: 'html'
    },
     {
        id: 3,
        name: 'javacript',
        type: 'code'
    },
    {
        id: 4,
        name: 'javacript',
        type: 'code'
    }
]

得到 new

var new = [
    {
        id: [1,2],
        name: 'css',
        type: 'html'
    },
     {
        id: [3,4],
        name: 'javacript',
        type: 'code'
    }
]

实现

var isEqual = (a, b) => a.name === b.name && b.type === b.type; 
var create = e => {
    e.id = [e.id]; 
    return e; 
}

var getNew = old => old.reduce((acc, cur) => {
    let hasItem = acc.some(e => {
        let temp = isEqual(e, cur); 
        if (temp) e.id.push(cur.id); 
        
        return temp; 
    });
    
    if (!hasItem) acc.push(create(cur))
    
    return acc; 
}, []);
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