请问我现在有三条数据，里面有一条是bid_status=1的，我要怎么只展示为1的，反之如果都不等于1，就展示全部等于0的，属于php的，打印出来的数据是json，不用管格式
"baojia": [
{
"bid_price": "*****",
"bid_status": "0",
"store_logo": "https://img.qcpjpt.com/20180818/1534584899_792.png",
"store_name": "我要入驻",
"store_credit": 0
},
{
"bid_price": "*****",
"bid_status": "0",
"store_logo": "https://img.qcpjpt.com/20180814/1534238896_521.jpg",
"store_name": "永丰汽配",
"store_credit": 0
},
{
"bid_price": "*****",
"bid_status": "1",
"store_logo": "https://img.qcpjpt.com/Public/uploads/20180530/%E5%BE%AE%E4%BF%A1%E5%9B%BE%E7%89%87_20180530140423.jpg",
"store_name": "华航通宝",
"store_credit": 100
}
],
相关代码
// 请把代码文本粘贴到下方（请勿用图片代替代码）
// 商家的报价针对该用户以外的用户屏蔽
$arr = [];
$arr_ = [];
foreach ($quoted_price as $key => $value) {
if( $request->param("user_id") != $reg['user_id'] ){
$arr[$key]['bid_price'] = "*****";
} else {
$arr[$key]['bid_price'] = $value['bid_price'];
}
if( $value['bid_status'] == 0 ){
$arr[$key]['bid_status'] = '0';
} else {
$arr[$key]['bid_status'] = '1';
}
$arr[$key]['store_logo'] = $value['store_logo'];
$arr[$key]['store_name'] = $value['store_name'];
$arr[$key]['store_credit'] = $value['store_credit'];
if( !empty($value['bid_status']) == 1 ){
$arr_ = $value['bid_status'];
}
}
$data["baojia"] = empty($arr) ? "暂无报价" : $arr ;
你这个应该在SQL里面去做
先COUNT 一下 bid_status = 1的数量 如果大于0 就取出 对应数据
如果COUNT==0 就取出 bid_status=0 的对应数据