每个子查询都会计算一个document针对它的相关度分数，然后bool综合所有分数，合并为一个分数，当然filter是不会计算分数的。示例：

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Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You may assume no duplicate exists in the array.

3.1 {代码...} 3.2 {代码...}

查看每列的格式：<class 'pandas.core.frame.DataFrame'>RangeIndex: 2324 entries, 0 to 2323Data columns (total 6 columns):date 2324 non-null objectid 2324 non-null objectword 2324 non-null objectrank1 2324 non-null objectnumber1 2324 non-null objecturl 2324 non-null objectdtypes: object(6)memo...

LeetCode 0700. Search in a Binary Search Tree二叉搜索树中的搜索【Easy】【Python】【二叉树】

前言 前往 ➡️ 我的博客 本文是根据自己的理解翻译而来，如有疑惑可查看原文 JavaScript engine fundamentals: optimizing prototypes。 本次暂定翻译三篇文章： JavaScript engine fundamentals: Shapes and Inline Caches(Published 14th June 2018) JavaScript engine fundamentals: optimizing prototypes(Published ...

用了 Docker 方才觉得生产环境终于有了他该有的样子，就像集装箱普及之后大型货轮的价值才逐渐体现出来，Docker 详细说明可查阅“官方文档”。本篇为 Docker Engine 的笔记，也就是我们通常说的 Docker，他包含了提供容器技术实现的 Docker daemon 及终端控制 Docker CLI 的应用程序。后续会继续发布 Docker Compose 和 Do...

即 在一个有序排列的数组中，找到目标值所在的起始下标和结束下标。如果该目标值不在数组中，则返回[-1,-1]题目中有一个特殊要求是时间复杂度为O(logn),也就是在暗示我们，不能只是单纯的按照顺序遍历数组，要尽量减去无效遍历。所以这题的核心思路为二分法遍历。

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

我的思路:1.首先得在board中寻找首元素可能出现的位置，对每个合法的开始位置进行dfs2.每次dfs的过程中，结合backtracing避免回退

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

Given a 2D board and a word, find if the word exists in the grid.The word can be constructed from letters of sequentially adjacentcell, where "adjacent" cells are those horizontally or verticallyneighboring. The same letter cell may not be used more than once. Example: board = [ ['A','B','C','E']...

The standard Storefront is used which is generated by Spartacus Schematics.

Assignment: The Rambler’s ProblemCOM1005 Machines and IntelligenceSemester 2: Experiments with AI TechniquesHeidi ChristensenUniversity of SheffieldVersion 1.1This assignment carries 30% of the marks for COM1005DUE DATE: Friday 21st May 2021 at 23:59 (UK Time)In this assignment you’ll experiment ...

React Native 是 Facebook 于2015年4月开源的跨平台移动应用开发框架，支持iOS和安卓两大平台。React Native 着力于提高多平台开发的开发效率 —— Learn once, write anywhere。背靠着巨人的肩膀出生，React Native 一路风光无限，经受住了重重考验。至今，它仍然是移动端跨平台开发的热门框架之一。

Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) connected 4-directionally (horizontal or vertical.) You may assume all four edges of the grid are surrounded by water.