The range of motion of the robot
Topic description
There is a square with m rows and n columns on the ground. A robot starts to move from the grid of coordinates 0 and 0, and can only move one grid in four directions: left, right, up and down at a time, but cannot enter the grid where the sum of the digits of the row and column coordinates is greater than k. For example, when k is 18, the robot is able to enter square (35,37) because 3+5+3+7 = 18. However, it cannot go into square (35,38) because 3+5+3+8 = 19.
- How many squares can the robot reach?
topic link : range of motion of the robot
code
/**
* 标题:机器人的运动范围
* 题目描述
* 地上有一个m行和n列的方格。一个机器人从坐标0,0的格子开始移动,每一次只能向左,右,上,下四个方向移动一格,但是不能进入行坐标和列坐标的数位
* 之和大于k的格子。 例如,当k为18时,机器人能够进入方格(35,37),因为3+5+3+7 = 18。但是,它不能进入方格(35,38),因为3+5+3+8 = 19。
* 请问该机器人能够达到多少个格子?
* 题目链接:
* https://www.nowcoder.com/practice/6e5207314b5241fb83f2329e89fdecc8?tpId=13&&tqId=11219&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking
*/
public class Jz66 {
private static final int[][] next = {{0, -1}, {0, 1}, {-1, 0}, {1, 0}};
private int cnt = 0;
private int rows;
private int cols;
private int threshold;
private int[][] digitSum;
/**
* 深度优先搜索(Depth First Search,DFS)
* 回溯是深度优先搜索的一种特例,它在一次搜索过程中需要设置一些本次搜索过程的局部状态,并在本次搜索结束之后清除状态。
* 而普通的深度优先搜索并不需要使用这些局部状态,虽然还是有可能设置一些全局状态。
*
* @param threshold
* @param rows
* @param cols
* @return
*/
public int movingCount(int threshold, int rows, int cols) {
this.rows = rows;
this.cols = cols;
this.threshold = threshold;
initDigitSum();
boolean[][] marked = new boolean[rows][cols];
dfs(marked, 0, 0);
return cnt;
}
private void dfs(boolean[][] marked, int r, int c) {
if (r < 0 || r >= rows || c < 0 || c >= cols || marked[r][c]) {
return;
}
marked[r][c] = true;
if (this.digitSum[r][c] > this.threshold) {
return;
}
cnt++;
for (int[] n : next) {
dfs(marked, r + n[0], c + n[1]);
}
}
private void initDigitSum() {
int[] digitSumOne = new int[Math.max(rows, cols)];
for (int i = 0; i < digitSumOne.length; i++) {
int n = i;
while (n > 0) {
digitSumOne[i] += n % 10;
n /= 10;
}
}
this.digitSum = new int[rows][cols];
for (int i = 0; i < this.rows; i++) {
for (int j = 0; j < this.cols; j++) {
this.digitSum[i][j] = digitSumOne[i] + digitSumOne[j];
}
}
}
public static void main(String[] args) {
Jz66 jz66 = new Jz66();
int i = jz66.movingCount(18, 20, 20);
System.out.println(i);
System.out.println(4 / 10);
}
}
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