习题笔记
今天解决一下 Higher Order Functions: Map, Filter, Reduce and more – Part 1 中最后的13个练习题,主要是关于闭包的(咦不对啊我明明是想看集合方面内容的。。。)。
Write a function applyTwice(f:(Float -> Float),x:Float) -> Float that takes a function f and a float x and aplies f to x twice i.e. f(f(x))
func applyTwice(f:(Float -> Float),x:Float) -> Float {
return f(f(x))
}
Write a function applyKTimes(f:(Float -> Float),x:Float,k:Int) -> Float that takes a function f and a float x and aplies f to x k times
// recursive version
func applyKTimes(f:(Float -> Float), x:Float, k:Int) -> Float
{
return k > 0 ? applyKTimes(f, f(x), k - 1) : x
}
// unrolled by hand
func applyKTimes(f:(Float -> Float),x:Float,k:Int) -> Float {
var y : Float = x
for _ in 0..<k {
y = f(y)
}
return y
}
Using applyKTimes write a function that raises x to the kth power
func getKthPower(x:Float, k:Int) -> Float{
return applyKTimes( {x * $0}, 1, k) // {x * $0} => {p in return x * p}
}
getKthPower(2.0, 3) // 8.0
Given an array of Users which have properties name:String and age:Int write a map function that returns an array of strings consisting of the user’s names
class User {
var name: String?
var age : Int?
init (name: String, age:Int) {
self.name = name
self.age = age
}
}
var user1 = User(name: "WHY1", age: 22)
var user2 = User(name: "WHY2", age: 23)
var user3 = User(name: "WHY3", age: 24)
var user4 = User(name: "WHY4", age: 25)
var users = [user1,user2,user3,user4]
var names: [String] = []
users.map({(user:User) in names.append(user.name!)})
println(names) // [WHY1, WHY2, WHY3, WHY4]
Given an array of of dictionaries containing keys for “name” and “age” write a map function that returns an array of users created from it
var users = [["name":"WHY1","age":"22"],["name":"WHY2","age":"23"],
["name":"WHY3","age":"24"],["name":"WHY4","age":"25"]]
var result = users.map({ (userDic:[String:String]) -> User in
return User(name: userDic["name"]!, age:userDic["age"]!.toInt()!)
})
Given an array of numbers write a filter method that only selects odd integers
var nums = [1,2,4,8,23,45,89,127]
var odds = nums.filter({ $0 % 2 == 0 }) // 2 4 8
Given an array of strings write a filter function that selects only strings that can be converted to Ints
var strs = ["2333","1223","callmewhy","callherhh"]
var intables = strs.filter({ $0.toInt() != nil }) // ["2333", "1223"]
Given an array of UIViews write a filter function that selects only those views that are a subclass of UILabel
import UIKit
var view1 = UIView()
var view2 = UIView()
var view3 = UILabel()
var view4 = UIView()
var views = [view1,view2,view3,view4]
var labels = views.filter({ $0.isKindOfClass(UILabel) }) // view3
Write a reduce function that takes an array of strings and returns a single string consisting of the given strings separated by newlines
var strs = ["str1","str2","str3","str4"]
var str = strs.reduce("", combine: { "\($0)\n\($1)" })
println(str)
Write a reduce function that finds the largest element in an array of Ints
var ints = [1,2,3,4,5,6]
var maxValue = ints.reduce(Int.min, { max($0, $1) }) // 6
You could implement a mean function using the reduce operation {$0 + $1 / Float(array.count)}. Why is this a bad idea?
var array = [1,2,3,4,6]
var mean = array.reduce(0, combine: {$0 + Float($1) / Float(array.count)}) // make division 5 times
There’s a problem you encounter when trying to implement a parallel version of reduce. What property should the operation have to make this easier ?
// TODO
Implement Church Numerals in Swift (This is a difficult and open ended exercise)
// TODO
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