Problem
Given a list of integers, which denote a permutation.
Find the previous permutation in ascending order.
Notice
The list may contains duplicate integers.
Example
For [1,3,2,3]
, the previous permutation is [1,2,3,3]
For [1,2,3,4]
, the previous permutation is [4,3,2,1]
Note
Solution
public class Solution {
public ArrayList<Integer> previousPermuation(ArrayList<Integer> nums) {
int pre = nums.size()-1;
while (pre > 0 && nums.get(pre-1) <= nums.get(pre)) pre--;
pre--;
if (pre >= 0) {
int cur = pre+1;
while (cur < nums.size() && nums.get(cur) < nums.get(pre)) cur++;
cur--;
int temp = nums.get(cur);
nums.set(cur, nums.get(pre));
nums.set(pre, temp);
}
int left = pre+1;
int right = nums.size()-1;
while (left < right) {
int temp = nums.get(left);
nums.set(left, nums.get(right));
nums.set(right, temp);
left++;
right--;
}
return nums;
}
}
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