Problem
Write a program to solve a Sudoku puzzle by filling the empty cells.
Empty cells are indicated by the character '.'.
You may assume that there will be only one unique solution.
Solution
public class Solution {
public void solveSudoku(char[][] board) {
if(board == null || board.length == 0)
return;
solve(board);
}
public boolean solve(char[][] board){
for(int i = 0; i < board.length; i++){
for(int j = 0; j < board[0].length; j++){
if(board[i][j] == '.'){
for(char c = '1'; c <= '9'; c++){//trial. Try 1 through 9 for each cell
if(isValid(board, i, j, c)){
board[i][j] = c; //Put c for this cell
if(solve(board))
return true; //If it's the solution return true
else
board[i][j] = '.'; //Otherwise go back
}
}
return false;
}
}
}
return true;
}
public boolean isValid(char[][] board, int i, int j, char c){
//Check colum
for(int row = 0; row < 9; row++)
if(board[row][j] == c)
return false;
//Check row
for(int col = 0; col < 9; col++)
if(board[i][col] == c)
return false;
//Check 3 x 3 block
for(int row = (i / 3) * 3; row < (i / 3) * 3 + 3; row++)
for(int col = (j / 3) * 3; col < (j / 3) * 3 + 3; col++)
if(board[row][col] == c)
return false;
return true;
}
}
public class Solution {
public void solveSudoku(char[][] board) {
solve(board, 0, 0);
}
private boolean solve(char[][] board, int row, int col) {
if (row == 9) return true;
int nextRow = col == 8 ? row+1 : row;
int nextCol = col == 8 ? 0 : col+1;
if (board[row][col] != '.') return solve(board, nextRow, nextCol);
for (int i = 1; i <= 9; i++) {
board[row][col] = (char) ('0'+i);
if (isValid(board, row, col) && solve(board, nextRow, nextCol)) return true;
}
board[row][col] = '.';
return false;
}
public boolean isValid(char[][] board, int row, int col) {
char cur = board[row][col];
for (int i = 0; i < 9; i++) {
if (i != row && cur == board[i][col]) return false;
}
for (int i = 0; i < 9; i++) {
if (i != col && cur == board[row][i]) return false;
}
int n = board.length;
int rowbox = row/3, colbox = col/3;
for (int i = rowbox*3; i < rowbox*3+3; i++) {
for (int j = colbox*3; j < colbox*3+3; j++) {
if (board[i][j] == cur && (i != row || j != col)) return false;
}
}
return true;
}
}
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