485. Max Consecutive Ones

Given a binary array, find the maximum number of consecutive 1s in
this array.

Example 1: Input: [1,1,0,1,1,1] Output: 3 Explanation: The first two
digits or the last three digits are consecutive 1s.

The maximum number of consecutive 1s is 3. Note:

The input array will only contain 0 and 1. The length of input array
is a positive integer and will not exceed 10,000

思路

遍历+计数, 遍历一遍数组, 当1时候计数器计数, 不是1时候归零

复杂度

时间O(n) 空间O(1)

代码

class Solution {
    public int findMaxConsecutiveOnes(int[] nums) {
        int res = 0, count = 0;
        for (int i = 0; i < nums.length; i++) {
            if (nums[i] == 1) {
                count++;
                res = Math.max(count, res);
            }
            else {
                count = 0;
            }
        }
        return res;
    }
}