Problem
Given a set of non-overlapping intervals, insert a new interval into the intervals (merge if necessary).
You may assume that the intervals were initially sorted according to their start times.
Example 1:
Input: intervals = [[1,3],[6,9]], newInterval = [2,5]
Output: [[1,5],[6,9]]
Example 2:
Input: intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]
Output: [[1,2],[3,10],[12,16]]
Explanation: Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].
Solution
with new list
class Solution {
public List<Interval> insert(List<Interval> intervals, Interval itvl) {
List<Interval> res = new ArrayList<>();
if (intervals == null || intervals.size() == 0) {
intervals.add(itvl);
return intervals;
}
int i = 0;
while (i < intervals.size() && intervals.get(i).end < itvl.start) {
res.add(intervals.get(i++));
}
while (i < intervals.size() && intervals.get(i).start <= itvl.end) {
itvl.start = Math.min(intervals.get(i).start, itvl.start);
itvl.end = Math.max(intervals.get(i).end, itvl.end);
i++;
}
res.add(itvl);
while (i < intervals.size()) {
res.add(intervals.get(i++));
}
return res;
}
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