Problem
Shuffle a set of numbers without duplicates.
Example:
// Init an array with set 1, 2, and 3.
int[] nums = {1,2,3};
Solution solution = new Solution(nums);
// Shuffle the array [1,2,3] and return its result. Any permutation of [1,2,3] must equally likely to be returned.
solution.shuffle();
// Resets the array back to its original configuration [1,2,3].
solution.reset();
// Returns the random shuffling of array [1,2,3].
solution.shuffle();
Solution
Note
- Random random = new Random();
- manipulate on a copy of given array, so that reset() would work;
- int j = random.nextInt(i+1); then swap A[i] and A[j].
class Solution {
private int[] N;
private Random random;
public Solution(int[] nums) {
this.N = nums;
random = new Random();
}
/** Resets the array to its original configuration and return it. */
public int[] reset() {
return N;
}
/** Returns a random shuffling of the array. */
public int[] shuffle() {
if (N == null) return null;
int[] A = N.clone();
for (int i = 0; i < A.length; i++) {
int j = random.nextInt(i+1);
swap(A, i, j);
}
return A;
}
private void swap(int[] nums, int i, int j) {
int temp = nums[i];
nums[i] = nums[j];
nums[j] = temp;
}
}
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