Problem
Numbers can be regarded as product of its factors. For example,
8 = 2 x 2 x 2;
= 2 x 4.
Write a function that takes an integer n and return all possible combinations of its factors.
Note:
You may assume that n is always positive.
Factors should be greater than 1 and less than n.
Example 1:
Input: 1
Output: []
Example 2:
Input: 37
Output:[]
Example 3:
Input: 12
Output:
[
[2, 6],
[2, 2, 3],
[3, 4]
]
Example 4:
Input: 32
Output:
[
[2, 16],
[2, 2, 8],
[2, 2, 2, 4],
[2, 2, 2, 2, 2],
[2, 4, 4],
[4, 8]
]
Solution
class Solution {
public List<List<Integer>> getFactors(int n) {
List<List<Integer>> res = new ArrayList<>();
if (n == 1) return res;
helper(n, 2, new ArrayList<>(), res);
return res;
}
private void helper(int n, int factor, List<Integer> temp, List<List<Integer>> res) {
if (n == 1 && temp.size() > 1) {
res.add(new ArrayList<>(temp));
}
//i starts from factor, to ensure that all factors equals or larger than 2
for (int i = factor; i <= n; i++) {
if (n%i == 0) {
temp.add(i);
helper(n/i, i, temp, res);
temp.remove(temp.size()-1);
}
}
}
}
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