JS实现一个new

实现一个new
代码如下:

var Dog = function(name) {
  this.name = name;
}
Dog.prototype.bark = function() {
  console.log('wang');
}
Dog.prototype.sayName = function() {
  console.log('my name is', this.name);
}

var xiaobai = new Dog('小白');
xiaobai.sayName();
xiaobai.bark();

//实现new
var _new = function() {
  var constructor = Array.prototype.shift.call(arguments);  //Dog
  var args = arguments;
  const obj = new Object();
  obj.__proto__ = constructor.prototype;
  constructor.call(obj, ...args);
  return obj;
}

var xiaohei = _new(Dog, '小黑');
xiaohei.bark();
xiaohei.sayName();

console.log(xiaohei instanceof Dog);    //true

---

解析

1. 思路:

   • 创建一个新对象obj
   • 把obj的__proto__指向Dog.prototype实现继承
   • 执行构造函数,传递参数,改变this指向,Dog.call(obj, ...args)
   • 返回obj

2. 解析:

   • var constructor = Array.prototype.shift.call(arguments); //Dog
     _new()的第一个参数是Dog,arguments返回的是_new的实参,因此constructor为Dog
   • var args = arguments; 获取剩下的参数
   • const obj = new Object(); 新建对象
   • obj.__proto__ = constructor.prototype; 把新建对象的__proto__指向Dog的原型链上
   • constructor.call(obj, ...args);传递参数,改变this指向

---

执行结果

• console.log(Dog.prototype);

• console.log(xiaobai);

• console.log(xiaohei);

• console.log(xiaohei instanceof Dog); true

instanceof运算符用于测试构造函数的prototype属性是否出现在对象的原型链中的任何位置