上篇文章写了如何在处理单列相同数据时让相同的项进行自动合并, 如果有多列合并的需求我们也应该可以从容应对...
(产品: 你们看我干嘛?)
废话不多说 上代码
HTML
<script src="//unpkg.com/vue/dist/vue.js"></script>
<script src="//unpkg.com/element-ui@2.3.7/lib/index.js"></script>
<div id="app">
<template>
<div>
<el-table :data="tableData6" :span-method="objectSpanMethod" border style="width: 100%; margin-top: 20px">
<el-table-column prop="name" label="姓名">
</el-table-column>
<el-table-column prop="amount1" label="数值 1(元)">
</el-table-column>
<el-table-column prop="amount2" label="数值 2(元)">
</el-table-column>
<el-table-column prop="amount3" label="数值 3(元)">
</el-table-column>
</el-table>
</div>
</template>
</div>
JS
var Main = {
data() {
return {
tableData6: [{
name: '部门1',
type: 0,
amount1: '跟单员1',
amount2: '成衣工厂1',
amount3: 10
}, {
name: '部门1',
type: 0,
amount1: '跟单员1',
amount2: '成衣工厂2',
amount3: 12
}, {
name: '部门1',
type: 0,
amount1: '跟单员1',
amount2: '成衣工厂3',
amount3: 9
}, {
name: '部门1',
type: 0,
amount1: '跟单员2',
amount2: '成衣工厂1',
amount3: 17
}, {
name: '部门1',
type: 0,
amount1: '跟单员2',
amount2: '成衣工厂2',
amount3: 15
},{
name: '部门1',
type: 0,
amount1: '跟单员2',
amount2: '成衣工厂3',
amount3: 10
}, {
name: '部门1总计',
type: 1,
amount1: '部门1跟单员',
amount2: '',
amount3: 12
},{
name: '部门2',
type: 0,
amount1: '跟单员3',
amount2: '成衣工厂1',
amount3: 10
}, {
name: '部门2',
type: 0,
amount1: '跟单员3',
amount2: '成衣工厂2',
amount3: 12
}, {
name: '部门2',
type: 0,
amount1: '跟单员3',
amount2: '成衣工厂3',
amount3: 9
}, {
name: '部门2',
type: 0,
amount1: '跟单员3',
amount2: '成衣工厂1',
amount3: 17
}, {
name: '部门2',
type: 0,
amount1: '跟单员4',
amount2: '成衣工厂2',
amount3: 15
},{
name: '部门2',
type: 0,
amount1: '跟单员4',
amount2: '成衣工厂3',
amount3: 10
}, {
name: '部门2总计',
type: 1,
amount1: '部门2跟单员',
amount2: '',
amount3: 12
}],
arr1:[],
arr2:[]
};
},
created() {
this.setdates(this.tableData6)
},
methods: {
setdates(arr) {
var obj = {},
k, arr1 = [];
for(var i = 0, len = arr.length; i < len; i++) {
k = arr[i].name;
if(obj[k])
obj[k]++;
else
obj[k] = 1;
}
console.log(obj)
//保存结果{el-'元素',count-出现次数}
for(var o in obj) {
for(let i=0;i<obj[o];i++){
if(i===0){
this.arr1.push(obj[o])
}else{
this.arr1.push(0)
}
}
}
console.log(this.arr1);
var obj2 = {},
j,arr2=[];
for(var i = 0, len = arr.length; i < len; i++) {
k = arr[i].amount1;
if(obj2[k])
obj2[k]++;
else
obj2[k] = 1;
}
console.log(obj2)
//保存结果{el-'元素',count-出现次数}
for(var o in obj2) {
for(let i=0;i<obj2[o];i++){
if(i===0){
this.arr2.push(obj2[o])
}else{
this.arr2.push(0)
}
}
}
console.log(this.arr2);
},
arraySpanMethod({ row, column, rowIndex, columnIndex }) {
if (rowIndex % 2 === 0) {
if (columnIndex === 0) {
return [1, 2];
} else if (columnIndex === 1) {
return [0, 0];
}
}
},
objectSpanMethod({ row, column, rowIndex, columnIndex }) {
if (columnIndex === 0 && this.tableData6[rowIndex].type == 0) {
let _row = this.arr1[rowIndex]
let _col = this.arr1[rowIndex] > 0 ? 1 : 0
return [_row,_col]
}else if(columnIndex === 0 && this.tableData6[rowIndex].type == 1){
return [1,3]
}else if (columnIndex === 1 && this.tableData6[rowIndex].type == 1){
return [0,0]
}else if (columnIndex === 2 && this.tableData6[rowIndex].type == 1){
return [0,0]
}else if (columnIndex === 1 && this.tableData6[rowIndex].type == 0){
let _row = this.arr2[rowIndex]
let _col = this.arr2[rowIndex] > 0 ? 1 : 0
return [_row,_col]
}
}
}
};
var Ctor = Vue.extend(Main)
new Ctor().$mount('#app')
最终效果
Fiddle代码预览地址https://jsfiddle.net/Tomatoro...
可能需要翻(程序员必备)
**粗体** _斜体_ [链接](http://example.com) `代码` - 列表 > 引用
。你还可以使用@
来通知其他用户。