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上篇文章写了如何在处理单列相同数据时让相同的项进行自动合并, 如果有多列合并的需求我们也应该可以从容应对...
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废话不多说 上代码

HTML
<script src="//unpkg.com/vue/dist/vue.js"></script>
<script src="//unpkg.com/element-ui@2.3.7/lib/index.js"></script>
<div id="app">
<template>
  <div>
    <el-table :data="tableData6" :span-method="objectSpanMethod" border style="width: 100%; margin-top: 20px">
      <el-table-column prop="name" label="姓名">
      </el-table-column>
      <el-table-column prop="amount1" label="数值 1(元)">
      </el-table-column>
      <el-table-column prop="amount2" label="数值 2(元)">
      </el-table-column>
      <el-table-column prop="amount3" label="数值 3(元)">
      </el-table-column>
    </el-table>
  </div>
</template>
</div>
JS
var Main = {
    data() {
      return {
        tableData6: [{
          name: '部门1',
          type: 0,
          amount1: '跟单员1',
          amount2: '成衣工厂1',
          amount3: 10
        }, {
          name: '部门1',
          type: 0,
          amount1: '跟单员1',
          amount2: '成衣工厂2',
          amount3: 12
        }, {
          name: '部门1',
          type: 0,
          amount1: '跟单员1',
          amount2: '成衣工厂3',
          amount3: 9
        }, {
          name: '部门1',
          type: 0,
          amount1: '跟单员2',
          amount2: '成衣工厂1',
          amount3: 17
        }, {
          name: '部门1',
          type: 0,
          amount1: '跟单员2',
          amount2: '成衣工厂2',
          amount3: 15
        },{
          name: '部门1',
          type: 0,
          amount1: '跟单员2',
          amount2: '成衣工厂3',
          amount3: 10
        }, {
          name: '部门1总计',
          type: 1,
          amount1: '部门1跟单员',
          amount2: '',
          amount3: 12
        },{
          name: '部门2',
          type: 0,
          amount1: '跟单员3',
          amount2: '成衣工厂1',
          amount3: 10
        }, {
          name: '部门2',
          type: 0,
          amount1: '跟单员3',
          amount2: '成衣工厂2',
          amount3: 12
        }, {
          name: '部门2',
          type: 0,
          amount1: '跟单员3',
          amount2: '成衣工厂3',
          amount3: 9
        }, {
          name: '部门2',
          type: 0,
          amount1: '跟单员3',
          amount2: '成衣工厂1',
          amount3: 17
        }, {
          name: '部门2',
          type: 0,
          amount1: '跟单员4',
          amount2: '成衣工厂2',
          amount3: 15
        },{
          name: '部门2',
          type: 0,
          amount1: '跟单员4',
          amount2: '成衣工厂3',
          amount3: 10
        }, {
          name: '部门2总计',
          type: 1,
          amount1: '部门2跟单员',
          amount2: '',
          amount3: 12
        }],
        arr1:[],
        arr2:[]
      };
    },
    created() {
        this.setdates(this.tableData6)
    },
    methods: {
        setdates(arr) {
          var obj = {},
              k, arr1 = [];
          for(var i = 0, len = arr.length; i < len; i++) {
              k = arr[i].name;
              if(obj[k])
                  obj[k]++;
              else
                  obj[k] = 1;
          }
          console.log(obj)
          //保存结果{el-'元素',count-出现次数}
          for(var o in obj) {
              for(let i=0;i<obj[o];i++){
                  if(i===0){
                    this.arr1.push(obj[o])
                }else{
                    this.arr1.push(0)
                }
              }
          }
          console.log(this.arr1);
          var obj2 = {},
                  j,arr2=[];
          for(var i = 0, len = arr.length; i < len; i++) {
              k = arr[i].amount1;
              if(obj2[k])
                  obj2[k]++;
              else
                  obj2[k] = 1;
          }
          console.log(obj2)
          //保存结果{el-'元素',count-出现次数}
          for(var o in obj2) {
              for(let i=0;i<obj2[o];i++){
                  if(i===0){
                    this.arr2.push(obj2[o])
                }else{
                    this.arr2.push(0)
                }
              }
          }
          console.log(this.arr2);
      },
      arraySpanMethod({ row, column, rowIndex, columnIndex }) {
        if (rowIndex % 2 === 0) {
          if (columnIndex === 0) {
            return [1, 2];
          } else if (columnIndex === 1) {
            return [0, 0];
          }
        }
      },

      objectSpanMethod({ row, column, rowIndex, columnIndex }) {
        if (columnIndex === 0 && this.tableData6[rowIndex].type == 0) {
            let _row = this.arr1[rowIndex]
          let _col = this.arr1[rowIndex] > 0 ? 1 : 0
          return [_row,_col]
        }else if(columnIndex === 0 && this.tableData6[rowIndex].type == 1){
                return [1,3]
        }else if (columnIndex === 1 && this.tableData6[rowIndex].type == 1){
                return [0,0]
        }else if (columnIndex === 2 && this.tableData6[rowIndex].type == 1){
                return [0,0]
        }else if (columnIndex === 1 && this.tableData6[rowIndex].type == 0){
            let _row = this.arr2[rowIndex]
          let _col = this.arr2[rowIndex] > 0 ? 1 : 0
          return [_row,_col]
        }
      }
    }
  };
var Ctor = Vue.extend(Main)
new Ctor().$mount('#app')
最终效果

clipboard.png

Fiddle代码预览地址https://jsfiddle.net/Tomatoro...
可能需要翻(程序员必备)


Tomatoro
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与未知的相遇,七分欢喜,三分孤寂.