最近经常使用到guava工具的东西,每次都要百度查询使用方法,现统一记录一下方便自己使用。
参考文章:Google guava工具类的介绍和使用、Guava工具类学习
引入依赖
<dependency>
<groupId>com.google.guava</groupId>
<artifactId>guava</artifactId>
<version>28.0-jre</version>
</dependency>
集合
创建集合
List<String> list = Lists.newArrayList();
Set<String> set = Sets.newHashSet();
Map<String, String> map = Maps.newHashMap();
不可变集合
ImmutableList<String> iList = ImmutableList.of("a", "b", "c");
ImmutableSet<String> iSet = ImmutableSet.of("e1", "e2");
ImmutableMap<String, String> iMap = ImmutableMap.of("k1", "v1", "k2", "v2");
Multimap
Multimap的特点其实就是可以包含有几个重复Key的value,你可以put进入多个不同value但是相同的key,但是又不是让后面覆盖前面的内容。它的业务场景:当你需要构造像Map<K, List<V>>或者Map<K, Set<V>>这样比较复杂的集合类型的数据结构,来做相应的业务逻辑处理。那Multimap在合适不过。
传统做法:
//Item就是封装的对象
Map<String,List<Item>> map = new HashMap<>();
for (Item item : list){
List<Item> tmp = map.get(item.getName());
if (null == tmp){
tmp = new ArrayList<>();
map.put(item.getName(),tmp);
}
tmp.add(item);
}
现在:
Multimap<String,Item> multiMap = ArrayListMultimap.create();
for (Item item : list){
multiMap.put(item.getName(),item);
}
类似的还有:
MultiSet: 无序+可重复 count()方法获取单词的次数 增强了可读性+操作简单
创建方式: Multiset<String> set = HashMultiset.create();
Multimap: key-value key可以重复
创建方式: Multimap<String, String> teachers = ArrayListMultimap.create();
BiMap: 双向Map(Bidirectional Map) 键与值都不能重复
创建方式: BiMap<String, String> biMap = HashBiMap.create();
Table: 双键的Map Map--> Table-->rowKey+columnKey+value //和sql中的联合主键有点像
创建方式: Table<String, String, Integer> tables = HashBasedTable.create();
将集合转换为特定规则的字符串
List<String> list = new ArrayList<String>();
list.add("aa");
list.add("bb");
list.add("cc");
String result = Joiner.on("-").join(list);
//result为 aa-bb-cc
把map集合转换为特定规则的字符串
Map<String, Integer> map = Maps.newHashMap();
map.put("xiaoming", 12);
map.put("xiaohong",13);
String result = Joiner.on(",").withKeyValueSeparator("=").join(map);
// result为 xiaoming=12,xiaohong=13
将String转换为特定的集合
//use guava
String str = "1-2-3-4-5-6";
List<String> list = Splitter.on("-").splitToList(str);
//list为 [1, 2, 3, 4, 5, 6]
String str = "1-2-3-4- 5- 6 ";
List<String> list = Splitter.on("-").omitEmptyStrings().trimResults().splitToList(str);
System.out.println(list);
//[1, 2, 3, 4, 5, 6] 可以忽略中间的空格
将String转换为map
String str = "xiaoming=11,xiaohong=23";
Map<String,String> map = Splitter.on(",").withKeyValueSeparator("=").split(str);
set的交集, 并集, 差集
HashSet setA = newHashSet(1, 2, 3, 4, 5);
HashSet setB = newHashSet(4, 5, 6, 7, 8);
SetView union = Sets.union(setA, setB);
System.out.println("union:");
for (Integer integer : union)
System.out.println(integer); //union:12345867
SetView difference = Sets.difference(setA, setB);
System.out.println("difference:");
for (Integer integer : difference)
System.out.println(integer); //difference:123
SetView intersection = Sets.intersection(setA, setB);
System.out.println("intersection:");
for (Integer integer : intersection)
System.out.println(integer); //intersection:45
map的交集,并集,差集
MapDifference differenceMap = Maps.difference(mapA, mapB);
differenceMap.areEqual();
Map entriesDiffering = differenceMap.entriesDiffering();
Map entriesOnlyOnLeft = differenceMap.entriesOnlyOnLeft();
Map entriesOnlyOnRight = differenceMap.entriesOnlyOnRight();
Map entriesInCommon = differenceMap.entriesInCommon();
MoreObjects
Person person = new Person("aa",11);
String str = MoreObjects.toStringHelper("Person").add("age", person.getAge()).toString();
System.out.println(str);
//输出Person{age=11}
字符串连接器Joiner
StringBuilder stringBuilder = new StringBuilder("hello");
// 字符串连接器,以|为分隔符,同时去掉null元素
Joiner joiner1 = Joiner.on("|").skipNulls();
// 构成一个字符串foo|bar|baz并添加到stringBuilder
stringBuilder = joiner1.appendTo(stringBuilder, "foo", "bar", null, "baz");
System.out.println(stringBuilder); // hellofoo|bar|baz
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