要求:依次执行fetch1=>fetch2=>fetch3,先执行fetch1,需要将fetch1的结果作为fetch2的参数,fetch2的结果作为fetch3的参数。
interface IEvents {
[key: string]: Array<Function>
}
class EventListener {
events: IEvents
constructor() {
this.events = {}
}
listen(key, fn) {
let fns = this.events[key];
if (fns) {
fns.push(fn)
} else {
this.events[key] = [fn]
}
}
on(key, payload) {
const fns = this.events[key]
if (fns && fns.length > 0) {
const fn = fns.shift()
fn(payload)
}
}
remove(key, fn) {
const fns = this.events[key]
if (!Array.isArray(fns)) return
const index = fns.indexOf(fn)
if (index !== -1) {
fns.splice(index, 1)
}
}
}
let listener = new EventListener()
const fetch1 = () => {
setTimeout(() => {
const res = {
current: 'fetch1',
next: 'fetch2'
}
console.log(res)
listener.on('fetch2', res)
})
}
const fetch2 = (payload) => {
setTimeout(() => {
const res = {
current: payload.next,
next: 'fetch3'
}
console.log(res)
listener.on('fetch3', res)
})
}
const fetch3 = (payload) => {
console.log({
current: payload.next,
next: ''
})
}
listener.listen('fetch2', fetch2)
listener.listen('fetch3', fetch3)
fetch1()
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