一,会改变原数组
1.移除数组末尾最后一项.pop(),返回删除的元素 如果你在一个空数组上调用 pop(),它返回 undefined
let word = ['a', 'b', 'c', 'd'];
let newArr = word.pop();
console.log(word); //['a', 'b', 'c']
console.log(newArr); //d
let nullArr = [];
console.log(nullArr.pop()); //undefined
2.在数组末尾添加一个或多个元素.push(),返回修改后数组长度
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let word = ['a', 'b', 'c', 'd'];
let newArr = word.push('e','f');
console.log(word); //['a', 'b', 'c', 'd', 'e', 'f']
console.log(newArr); //6
3.移除数组第一项.shift(),返回移除的元素
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let word = ['a', 'b', 'c', 'd'];
let newArr = word.shift();
console.log(word); //['b', 'c', 'd']
console.log(newArr); //a
4.在数组头部添加一个或多个元素.unshift(),返回修改后数组长度
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let word = ['a', 'b', 'c', 'd'];
let newArr = word.unshift('11','22');
console.log(word); //['11', '22', 'a', 'b', 'c', 'd']
console.log(newArr); //6
5.对数组元素排序.sort(),返回排序后的数组
默认排序顺序是根据字符串Unicode码点
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let fruit = ['cherries', 'apples', 'bananas'];
console.log(fruit.sort()); // ['apples', 'bananas', 'cherries']
let scores = [1, 10, 21, 2];
console.log(scores.sort());
// [1, 10, 2, 21]
// 注意10在2之前,
// 因为在 Unicode 指针顺序中"10"在"2"之前
let things = ['word', 'Word', '1 Word', '2 Words'];
console.log(things.sort());
// ['1 Word', '2 Words', 'Word', 'word']
// 在Unicode中, 数字在大写字母之前,
// 大写字母在小写字母之前.
function compare(a, b) {
if(a < b) {
return -1;
}else if(a > b) {
return 1;
}else {
return 0;
}
}
let num = [1, 10, 21, 2];
console.log(num.sort(compare)); //[1, 2, 10, 21]
6.颠倒数组元素.reverse(),返回颠倒后的数组
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let word = ["a", "b", "c", "d"];
let newArr = word.reverse();
console.log(word); //["d", "c", "b", "a"]
console.log(newArr); //["d", "c", "b", "a"]
7.删除或插入元素.splice(),返回数组删除的项,没有删除的项,返回空数组
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var word = ['a', 'b', 'c', 'd'];
//删除,前闭后开
var newArr = word.splice(0,2);
console.log(word); //["c", "d"]
console.log(newArr); //["a", "b"]
//插入,当前数组索引1处插入hello
var newArr = word.splice(1,0,'hello');
console.log(word); //["c", "hello", "d"]
console.log(newArr); //[]
//替换
var newArr = word.splice(1,1,'world');
console.log(word); //["c", "world", "d"]
console.log(newArr); //["hello"]
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