js中reduce的神奇用法

最近经常在项目中经常看到别人用reduce处理数据，很是牛掰，很梦幻， 不如自己琢磨琢磨。

先看w3c语法

array.reduce(function(total, currentValue, currentIndex, arr), initialValue);
/*
  total: 必需。初始值, 或者计算结束后的返回值。
  currentValue： 必需。当前元素。
  currentIndex： 可选。当前元素的索引；                     
  arr： 可选。当前元素所属的数组对象。
  initialValue: 可选。传递给函数的初始值，相当于total的初始值。
*/

常见用法

数组求和

const arr = [12, 34, 23];
const sum = arr.reduce((total, num) => total + num);
<!-- 设定初始值求和 -->
const arr = [12, 34, 23];
const sum = arr.reduce((total, num) => total + num, 10);  // 以10为初始值求和
<!-- 对象数组求和 -->
var result = [
  { subject: 'math', score: 88 },
  { subject: 'chinese', score: 95 },
  { subject: 'english', score: 80 }
];
const sum = result.reduce((accumulator, cur) => accumulator + cur.score, 0); 
const sum = result.reduce((accumulator, cur) => accumulator + cur.score, -10);  // 总分扣除10分

数组最大值

const a = [23,123,342,12];
const max = a.reduce(function(pre,cur,inde,arr){return pre>cur?pre:cur;}); // 342

进阶用法

数组对象中的用法

<!-- 比如生成“老大、老二和老三” -->
const objArr = [{name: '老大'}, {name: '老二'}, {name: '老三'}];
const res = objArr.reduce((pre, cur, index, arr) => {
  if (index === 0) {
    return cur.name;
  }
  else if (index === (arr.length - 1)) {
    return pre + '和' + cur.name;
  }
  else {
    return pre + '、' + cur.name;
  }
}, '');

求字符串中字母出现的次数

const str = 'sfhjasfjgfasjuwqrqadqeiqsajsdaiwqdaklldflas-cmxzmnha';
const res = str.split('').reduce((accumulator, cur) => {accumulator[cur] ? accumulator[cur]++ : accumulator[cur] = 1; return accumulator;}, {});

数组转数组

<!-- 按照一定的规则转成数组 -->
var arr1 = [2, 3, 4, 5, 6]; // 每个值的平方
var newarr = arr1.reduce((accumulator, cur) => {accumulator.push(cur * cur); return accumulator;}, []);

数组转对象

<!-- 按照id 取出stream -->
var streams = [{name: '技术', id: 1}, {name: '设计', id: 2}];
var obj = streams.reduce((accumulator, cur) => {accumulator[cur.id] = cur; return accumulator;}, {});

高级用法

多维的叠加执行操作

<!-- 各科成绩占比重不一样， 求结果 -->
var result = [
  { subject: 'math', score: 88 },
  { subject: 'chinese', score: 95 },
  { subject: 'english', score: 80 }
];
var dis = {
    math: 0.5,
    chinese: 0.3,
    english: 0.2
};
var res = result.reduce((accumulator, cur) => dis[cur.subject] * cur.score + accumulator, 0);

<!-- 加大难度， 商品对应不同国家汇率不同，求总价格 -->
var prices = [{price: 23}, {price: 45}, {price: 56}];
var rates = {
  us: '6.5',
  eu: '7.5',
};
var initialState = {usTotal:0, euTotal: 0};
var res = prices.reduce((accumulator, cur1) => Object.keys(rates).reduce((prev2, cur2) => {
  console.log(accumulator, cur1, prev2, cur2);
  accumulator[`${cur2}Total`] += cur1.price * rates[cur2];
  return accumulator;
}, {}), initialState);

var manageReducers = function() {
  return function(state, item) {
    return Object.keys(rates).reduce((nextState, key) => {
        state[`${key}Total`] += item.price * rates[key];
        return state;
      }, {});
  }
};
var res1= prices.reduce(manageReducers(), initialState);

扁平一个二维数组

var arr = [[1, 2, 8], [3, 4, 9], [5, 6, 10]];
var res = arr.reduce((x, y) => x.concat(y), []);

对象数组去重

const hash = {};
  chatlists = chatlists.reduce((obj, next: Object) => {
    const hashId = `${next.topic}_${next.stream_id}`;
    if (!hash[hashId]) {
      hash[`${next.topic}_${next.stream_id}`] = true;
      obj.push(next);
    }
    return obj;
  }, []);

compose函数

redux compose源码实现

function compose(...funs) {
    if (funs.length === 0) {
        return arg => arg;
    }
    if (funs.length === 1) {
       return funs[0];
    }
    return funs.reduce((a, b) => (...arg) => a(b(...arg)))

}

参考文章
https://developer.mozilla.org...
https://www.liaoxuefeng.com/w...
https://aotu.io/notes/2016/04...