用Python写个开心消消乐小游戏

Python小二

提到开心消消乐这款小游戏,相信大家都不陌生,其曾在 2015 年获得过玩家最喜爱的移动单机游戏奖,受欢迎程度可见一斑,本文我们使用 Python 来做个简单的消消乐小游戏。

实现

消消乐的构成主要包括三部分:游戏主体、计分器、计时器,下面来看一下具体实现。

先来看一下游戏所需 Python 库。

import os
import sys
import time
import pygame
import random

定义一些常量,比如:窗口宽高、网格行列数等,代码如下:

WIDTH = 400
HEIGHT = 400
NUMGRID = 8
GRIDSIZE = 36
XMARGIN = (WIDTH - GRIDSIZE * NUMGRID) // 2
YMARGIN = (HEIGHT - GRIDSIZE * NUMGRID) // 2
ROOTDIR = os.getcwd()
FPS = 30

接着创建一个主窗口,代码如下:

pygame.init()
screen = pygame.display.set_mode((WIDTH, HEIGHT))
pygame.display.set_caption('消消乐')

看一下效果:

再接着在窗口中画一个 8 x 8 的网格,代码如下:

screen.fill((255, 255, 220))
# 游戏界面的网格绘制
def drawGrids(self):
    for x in range(NUMGRID):
        for y in range(NUMGRID):
            rect = pygame.Rect((XMARGIN+x*GRIDSIZE, YMARGIN+y*GRIDSIZE, GRIDSIZE, GRIDSIZE))
            self.drawBlock(rect, color=(255, 165, 0), size=1
# 画矩形 block 框
def drawBlock(self, block, color=(255, 0, 0), size=2):
    pygame.draw.rect(self.screen, color, block, size)

看一下效果:

再接着在网格中随机放入各种拼图块,代码如下:

while True:
    self.all_gems = []
    self.gems_group = pygame.sprite.Group()
    for x in range(NUMGRID):
        self.all_gems.append([])
        for y in range(NUMGRID):
            gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+x*GRIDSIZE, YMARGIN+y*GRIDSIZE-NUMGRID*GRIDSIZE], downlen=NUMGRID*GRIDSIZE)
            self.all_gems[x].append(gem)
            self.gems_group.add(gem)
    if self.isMatch()[0] == 0:
        break

看一下效果:

再接着加入计分器和计时器,代码如下:

# 显示得分
def drawScore(self):
    score_render = self.font.render('分数:'+str(self.score), 1, (85, 65, 0))
    rect = score_render.get_rect()
    rect.left, rect.top = (55, 15)
    self.screen.blit(score_render, rect)
# 显示加分
def drawAddScore(self, add_score):
    score_render = self.font.render('+'+str(add_score), 1, (255, 100, 100))
    rect = score_render.get_rect()
    rect.left, rect.top = (250, 250)
    self.screen.blit(score_render, rect)
# 显示剩余时间
def showRemainingTime(self):
    remaining_time_render = self.font.render('倒计时: %ss' % str(self.remaining_time), 1, (85, 65, 0))
    rect = remaining_time_render.get_rect()
    rect.left, rect.top = (WIDTH-190, 15)
    self.screen.blit(remaining_time_render, rect)

看一下效果:

当设置的游戏时间用尽时,我们可以生成一些提示信息,代码如下:

while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            pygame.quit()
            sys.exit()
        if event.type == pygame.KEYUP and event.key == pygame.K_r:
            flag = True
    if flag:
        break
    screen.fill((255, 255, 220))
    text0 = '最终得分: %s' % score
    text1 = '按 R 键重新开始'
    y = 140
    for idx, text in enumerate([text0, text1]):
        text_render = font.render(text, 1, (85, 65, 0))
        rect = text_render.get_rect()
        if idx == 0:
            rect.left, rect.top = (100, y)
        elif idx == 1:
            rect.left, rect.top = (100, y)
        y += 60
        screen.blit(text_render, rect)
    pygame.display.update()

看一下效果:

说完了游戏图形化界面相关的部分,我们再看一下游戏的主要处理逻辑。

我们通过鼠标来操纵拼图块,因此程序需要检查有无拼图块被选中,代码实现如下:

def checkSelected(self, position):
    for x in range(NUMGRID):
        for y in range(NUMGRID):
            if self.getGemByPos(x, y).rect.collidepoint(*position):
                return [x, y]
    return None

我们需要将鼠标连续选择的拼图块进行位置交换,代码实现如下:

def swapGem(self, gem1_pos, gem2_pos):
    margin = gem1_pos[0] - gem2_pos[0] + gem1_pos[1] - gem2_pos[1]
    if abs(margin) != 1:
        return False
    gem1 = self.getGemByPos(*gem1_pos)
    gem2 = self.getGemByPos(*gem2_pos)
    if gem1_pos[0] - gem2_pos[0] == 1:
        gem1.direction = 'left'
        gem2.direction = 'right'
    elif gem1_pos[0] - gem2_pos[0] == -1:
        gem2.direction = 'left'
        gem1.direction = 'right'
    elif gem1_pos[1] - gem2_pos[1] == 1:
        gem1.direction = 'up'
        gem2.direction = 'down'
    elif gem1_pos[1] - gem2_pos[1] == -1:
        gem2.direction = 'up'
        gem1.direction = 'down'
    gem1.target_x = gem2.rect.left
    gem1.target_y = gem2.rect.top
    gem1.fixed = False
    gem2.target_x = gem1.rect.left
    gem2.target_y = gem1.rect.top
    gem2.fixed = False
    self.all_gems[gem2_pos[0]][gem2_pos[1]] = gem1
    self.all_gems[gem1_pos[0]][gem1_pos[1]] = gem2
    return True

每一次交换拼图块时,我们需要判断是否有连续一样的三个及以上拼图块,代码实现如下:

def isMatch(self):
    for x in range(NUMGRID):
        for y in range(NUMGRID):
            if x + 2 < NUMGRID:
                if self.getGemByPos(x, y).type == self.getGemByPos(x+1, y).type == self.getGemByPos(x+2, y).type:
                    return [1, x, y]
            if y + 2 < NUMGRID:
                if self.getGemByPos(x, y).type == self.getGemByPos(x, y+1).type == self.getGemByPos(x, y+2).type:
                    return [2, x, y]
    return [0, x, y]

当出现三个及以上拼图块时,需要将这些拼图块消除,代码实现如下:

def removeMatched(self, res_match):
    if res_match[0] > 0:
        self.generateNewGems(res_match)
        self.score += self.reward
        return self.reward
    return 0

将匹配的拼图块消除之后,我们还需要随机生成新的拼图块,代码实现如下:

def generateNewGems(self, res_match):
    if res_match[0] == 1:
        start = res_match[2]
        while start > -2:
            for each in [res_match[1], res_match[1]+1, res_match[1]+2]:
                gem = self.getGemByPos(*[each, start])
                if start == res_match[2]:
                    self.gems_group.remove(gem)
                    self.all_gems[each][start] = None
                elif start >= 0:
                    gem.target_y += GRIDSIZE
                    gem.fixed = False
                    gem.direction = 'down'
                    self.all_gems[each][start+1] = gem
                else:
                    gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+each*GRIDSIZE, YMARGIN-GRIDSIZE], downlen=GRIDSIZE)
                    self.gems_group.add(gem)
                    self.all_gems[each][start+1] = gem
            start -= 1
    elif res_match[0] == 2:
        start = res_match[2]
        while start > -4:
            if start == res_match[2]:
                for each in range(0, 3):
                    gem = self.getGemByPos(*[res_match[1], start+each])
                    self.gems_group.remove(gem)
                    self.all_gems[res_match[1]][start+each] = None
            elif start >= 0:
                gem = self.getGemByPos(*[res_match[1], start])
                gem.target_y += GRIDSIZE * 3
                gem.fixed = False
                gem.direction = 'down'
                self.all_gems[res_match[1]][start+3] = gem
            else:
                gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+res_match[1]*GRIDSIZE, YMARGIN+start*GRIDSIZE], downlen=GRIDSIZE*3)
                self.gems_group.add(gem)
                self.all_gems[res_match[1]][start+3] = gem
            start -= 1

之后反复执行这个过程,直至耗尽游戏时间,游戏结束。

最后,我们动态看一下游戏效果。

总结

本文我们使用 Python 实现了一个简单的消消乐游戏,有兴趣的可以对游戏做进一步扩展,比如增加关卡等。

源码在公众号 Python小二 后台回复 200727 获取。

声明:本文作者为本人,但非首发于个人号
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