为什么random.next 返回的都是一个数字

Question

public static void Main(string[] args)
        {
            int[] ints = new int[50];
            for (int i = 0; i < ints.Length; i++)
            {
                Random random = new Random();

                ints[i] = random.Next();
            }

            new Rectangle().print(ints);
        }

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Answer 1

Random random = new Random();
for (int i = 0; i < ints.Length; i++)
{
    ints[i] = random.Next();
}

要一直用同一个random

Answer 2

https://blog.csdn.net/w790634... 可以看下