let arr =[{id:1,name:2,job:1},{id:2,name:1,job:1},{id:3,name:2,job:0},{id:4,name:0,job:0}];
我想实现arr遍历后,把name>0的拆成一个新对象,把job大于的0的也拆成一个新对象,最后生成一个新数组,类似下面的代码。我想知道怎么用ES6实现?或者有什么高效的办法?
newArr =[{id:1,job:1},{id:2,job:1},{id:1,name:2},{id:2,name:1},{id:3,name:2}];
是这意思吗?