python 正则表达式匹配连续相同字符的问题

Question

a='aa'
b='aaa'
c=re.findall(a,b)
print(c)# 输出结果为['aa']，只有一处匹配位置
但是我觉得应该有两处匹配，输出结果应为['aa','aa'] 怎样解决这个问题啊？

Answer 1

正则好像不太好弄。可以用代码实现。

其实这个跟leetcode这个题比较像：https://leetcode-cn.com/probl...

简单点就这么写。

In [3]: a = 'aa'

In [4]: b = 'aaa'

In [5]: res_list = []
   ...: for i in range(0, len(b)-len(a)+1):
   ...:     if b[i:i+len(a)] == a:
   ...:         res_list.append(a)
   ...: print(res_list)
['aa', 'aa']

Answer 2

文档里面写了的，如下

?re.findall(pattern, string, flags=0)
Return all non-overlapping matches of pattern in string, as a list of strings. The string is scanned left-to-right, and matches are returned in the order found. If one or more groups are present in the pattern, return a list of groups; this will be a list of tuples if the pattern has more than one group. Empty matches are included in the result.

是非重叠匹配