统计字符串出现的次数

Question

统计每个字符出现的次数？这个怎么写比较简单？
babajpppwwwonjust

Answer 1

//Array.from('babajpppwwwonjust')
'babajpppwwwonjust'.split('').reduce((obj, s) => {
    obj[s] = (obj[s] || 0) + 1
    return obj
}, {})

Answer 2

只会遍历不重复的字符

const charTotal =(str='')=>{
  let res = {};
  do {
    let s = str.substr(0,1);
    let reg = new RegExp(s,'ig');
    let num = str.match(reg).length;
    res[s] = num;
    str = str.replace(reg,'');
  } while (str.length>0);
  return res;
}
let str = 'babajpppwwwonjust';
charTotal(str);

看了一下相似问题 https://segmentfault.com/q/10...
大佬们也有相同的解决方法。

Answer 3

__author__ = 'Kangjie Lee'
__mtime__  = '2021/09/03 13:28:04'
__email__  = '[e-mail]'
 
# 方法1：统计单个字符出现次数
def str_count_one(strs:str, find_str:str):
    return strs.count(find_str)
 
# 方法2：统计全部字符出现次数
def str_count_three(strs:str):
    from collections import Counter
    return Counter(strs)
 
if __name__ == '__main__':
   aa =  str_count_one('sfbabajpppwwwonjustsfdsf', 's')
   bb =   str_count_three('babajpppwwwonjust')


   print(aa)
   print(bb)