NameError: name 'request' is not defined, in Django forms

Question

如何在 forms.py 中获取当前登录用户？我正在尝试预填充当前用户的电子邮件字段。

 class ContactMe(forms.Form):
    name                 = forms.CharField(label = "Name")
    email_address        = forms.CharField(label = "Email Address", intital = request.user.email)
    subject              = forms.CharField(label = "Subject")
    message              = forms.CharField(label = "Message", widget=forms.Textarea(attrs={'cols': 10, 'rows': 3}))
    additional_comments  = forms.CharField(required = False)
    class Meta:
        model = Contact_me

我尝试将来自 views.py 的请求传递为：

 contact_form = ContactMe(request.POST or None, request)

然后在类中接收请求 ContactMe 如下：

 class ContactMe(forms.Form, request):
    name                 = forms.CharField(label = "Name")
    email_address        = forms.CharField(label = "Email Address", intital = **request.user.email**)
    subject              = forms.CharField(label = "Subject")
    message              = forms.CharField(label = "Message", widget=forms.Textarea(attrs={'cols': 10, 'rows': 3}))
    additional_comments  = forms.CharField(required = False)
    class Meta:
        model = Contact_me

它抛出错误 NameError: name 'request' is not defined 。我知道可以在 html , models.py , views.py 访问请求。如何在 forms.py 中获取它？

views.py ：

 def list_posts(request):
    request.session.set_expiry(request.session.get_expiry_age())        # Renew session expire time
    instance_list = Post.objects.all()
    register_form = UserRegisterForm(data=request.POST or None)
    if register_form.is_valid():
        personal.views.register_form_validation(request, register_form)

    login_form = UserLoginForm(request.POST or None)
    if login_form.is_valid() :
        personal.views.login_form_validation(request, login_form)

    feedback_form = FeedbackForm(request.POST or None)
    if feedback_form.is_valid() :
        personal.views.feedback_form_validation(request, feedback_form)

    contact_form = ContactMe(request.POST or None, request)
    if contact_form.is_valid() :
    personal.views.contact_form_validation(request, login_form)

    if request.POST and not(register_form.is_valid() or login_form.is_valid()):
        if request.POST.get("login"):
            return accounts.views.login_view(request)
        else:
            return accounts.views.register_view(request)

    template = 'blog/archives.html'
    dictionary = {

        "object_list"   : content,
        "register_form" : register_form,
        "login_form"    : login_form,
        "feedback_form" : feedback_form,
        "contact_form"  : contact_form,
    }
    return render(request,template,dictionary)

原文由 sagar_jeevan 发布，翻译遵循 CC BY-SA 4.0 许可协议

Answer 1

您在构造表单类时试图传递 request 。此时没有请求。该请求仅存在于您的视图函数中。因此，您应该在构造表单实例时在视图函数中传递请求。要预填充表单，您可以使用表单构造函数的 initial 关键字。它以字段名称和值的字典作为输入。

例子：

 #views.py
from django.shortcuts import render
from django import forms

class TestForm(forms.Form):
    foo = forms.CharField()

def test_form(request):
    form = TestForm(initial=dict(foo=request.<some_property>))
    context = dict(form=form)
    template_name = 'testapp/test.html'
    return render(request, template_name, context)

原文由 Martin Bierbaum 发布，翻译遵循 CC BY-SA 3.0 许可协议

Answer 2

这一行是错误的 class ContactMe(forms.Form, request) 。

（提示： request 不是您表单的基类）

正确的方法是在 __init__ 方法中访问 user 形式：

 class ContactMe(forms.ModelForm):

    class Meta:
         model = Contact_me
         fields = '__all__'

    def __init__(self, *args, **kwargs):
        user = kwargs.pop('user', None)
        super(ContactMe, self).__init__(*args, **kwargs)

views.py 中的对应行：

 contact_form = ContactMe(request.POST, user=request.user)

原文由 arie 发布，翻译遵循 CC BY-SA 3.0 许可协议