如何实现软键盘弹出后,整体布局不变?

如何实现软键盘弹出后,整体布局不变

阅读 470
1 个回答

通过expandSafeArea属性把组件扩展其安全区域,使页面整体布局保持不变。可参考如下代码:

// xxx.ets 
@Entry 
@Component 
struct TextInputExample { 
  scroller: Scroller = new Scroller(); 
  @State Text: string = ''; 
 
  build() { 
    Scroll(this.scroller) { 
      Column({ space: 20 }) { 
        TextInput({ placeholder: 'Please enter the content.' }) 
          .expandSafeArea([SafeAreaType.KEYBOARD]) 
          .type(InputType.Password) 
          .margin({ top: 200 }) 
        TextInput({ placeholder: 'Please enter the content.' }) 
          .expandSafeArea([SafeAreaType.KEYBOARD]) 
          .margin({ top: 200 }) 
        Text(`UserName:${this.Text}`) 
          .expandSafeArea([SafeAreaType.KEYBOARD]) 
          .width('80%') 
          .margin({ top: 200 }) 
        TextInput({ placeholder: 'Please enter a user name.', text: this.Text }) 
          .expandSafeArea([SafeAreaType.KEYBOARD]) 
          .margin({ top: 200 }) 
          .onChange((value: string) => { 
            this.Text = value; 
          }) 
      } 
      .width('100%') 
    } 
    .scrollBar(BarState.Off) 
  } 
}
撰写回答
你尚未登录,登录后可以
  • 和开发者交流问题的细节
  • 关注并接收问题和回答的更新提醒
  • 参与内容的编辑和改进,让解决方法与时俱进