[C] memset的第二个参数为何不能在执行的时候确定？？？（已解决）

Question

当使用memset的时候，初始化的数据如下：

134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 
134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 
134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 
134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 134744072 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 

Answer 1

该问题主要自身对memset的理解不够透彻。

NAME
       memset - fill memory with a constant byte

SYNOPSIS
       #include <string.h>

       void *memset(void *s, int c, size_t n);

DESCRIPTION
       The memset() function fills the first n bytes of the memory area pointed to by s with the constant byte c.

code中alphabet定义的是int而非char，它只是初始化前n byte，而不是4*n byte。