怎么建立一个每项是十六进制数字的数组?

Question

下面是我的代码:

NSArray *colorArray = [@0xffa500, @0xadd8e6, @0x6699cc, @0x99cc99, 
@0x99cccc, @0x669999, @0x3399cc, @0x6699ff, @0xfaafbe, @0x800080, 
@0x808080, @0x008000, @0xa52a2a];

Answer 1

可以存储时存储字符串

NSArray *colorArray = @[@"0xffa500", @"0xadd8e6", @"0x6699cc", @"0x99cc99",
                        @"0x99cccc", @"0x669999", @"0x3399cc", @"0x6699ff",
                        @"0xfaafbe", @"0x800080", @"0x808080", @"0x008000",
                        @"0xa52a2a"];

- (NSUInteger)hex:(NSString *)str
{
   NSUInteger outValue = 0;
   [[NSScanner scannerWithString:str]scanHexInt:&outValue];
   return outValue;
}

for (id obj in colorArray)
    NSLog(@"0x%X",[self hex:obj]);

不过貌似这样其实就可以了

NSArray *colorArray = @[@0xffa500, @0xadd8e6, @0x6699cc, @0x99cc99,
                        @0x99cccc, @0x669999, @0x3399cc, @0x6699ff, @0xfaafbe, @0x800080,
                        @0x808080, @0x008000, @0xa52a2a];