django如何建立指向自身的外键

Question

如题，试着用django系统做一个微博系统，在建立user model时使用的是OneToOne的方式扩展django.contrib.auth.admin的User,但出了点问题，想实现微博上关注和粉丝的功能，这样写报错

class weiboUser(models.Model):
    user = models.OneToOneField(User)
    fans = models.ForeignKey(weiboUser,related_name="fans")
    focus  = models.ForeignKey(weiboUser,related_name="focus")

所以想问一下如何在model下建立指向自身model的外键？谢谢。

补充，参照了官方文档，做了以下修改，虽然不报错了，但无法同步数据库，求高人继续指导。

class weiboUser(models.Model):
    user = models.OneToOneField(User)
    fans = models.ManyToManyField('self',symmetrical=False)
    focus  = models.ManyToManyField('self',symmetrical=False)

Answer 1

目测楼主不懂数据库

Answer 2

需要建立一个抽象类为父类，用代码说话：

class AbstractNavi(models.Model):  
    parent = models.ForeignKey('self',blank=True, null=True, related_name='child')  
    class Meta:  
        abstract = True  
    
class Navi(AbstractNavi):  
    """ 
    Navi has four type: goods, news, page and custom 
    """  
    STYLE_CHOICES = (  
        ('goods', 'goods'),  
        ('news', 'news'),  
        ('page', 'page'),  
        ('custom', 'custom'),  
    )  
    name = models.SlugField()  
    #parent = models.ForeignKey('self', null=True, blank=True, related_name='child')  
    style = models.SlugField(choices=STYLE_CHOICES)  
    url = models.CharField(max_length=100, default='#')  
    sort = models.IntegerField(default=1)  
    is_display = models.BooleanField(default=True)  
    def __unicode__(self):  
        return self.name