请教关于django获取参数的问题

Question

这是网站结构

mywebsute下的urls.py内容：

from django.conf.urls import patterns, include, url
from django.contrib import admin

urlpatterns = patterns('',
    url(r'^admin/', include(admin.site.urls)),
    url(r'/(?P<id>/d{2})$','index.views.index')
)

然后index下views.py的内容：

from django.shortcuts import render_to_response

# Create your views here.
def index(req, id):
    return render_to_response('index.html', {'id':id})

那么现在问题是，我在浏览器输入“127.0.0.1:8000/12”，浏览器提示404 not found:

Using the URLconf defined in mywebsite.urls, Django tried these URL patterns, in this order:
1.^admin/
2./(?P/d{2})$
The current URL, 12, didn't match any of these.

我只是希望在首页上获取一个数字给id，为什么会这样呢？
补充一下：Django 1.7，Python 3.4

Answer 1

这块写反了吧？是\d而不是/d

url(r'/(?P<id>\d{2})$','index.views.index')

参考：https://docs.djangoproject.com/en/1.7/topics/http/urls/#named-groups