sql高效查询的问题

Question

有个表，里面有xx_id、time和type两个字段，大体是这样

xx_id	time	type
1	2015-07-08 12:00:00	0
1	2015-07-08 12:05:01	1
2	2015-07-08 12:25:11	0
2	2015-07-08 12:35:21	1

我想查到xx_id相同并对应type为0，1 time时间相差10分钟内的个数，怎么组织sql最高效。

Answer 1

$time = time() - 600;

select xx_id,count(xx_id) count from tablename where type = 1 and time > $time group by xx_id;