java中String.format(format,args)中的args是动态的，如何定义format?

Question

java中String.format(format,args)中的args是动态的，如何定义format?

Answer 1

来自intellij

format(String format, Object... args)

public static String format(String var0, Object... var1) {
        return (new Formatter()).format(var0, var1).toString();
    }

public Formatter format(Locale var1, String var2, Object... var3) {
        this.ensureOpen();
        int var4 = -1;
        int var5 = -1;
        Formatter.FormatString[] var6 = this.parse(var2);

        for(int var7 = 0; var7 < var6.length; ++var7) {
            Formatter.FormatString var8 = var6[var7];
            int var9 = var8.index();

            try {
                switch(var9) {
                case -2:
                    var8.print((Object)null, var1);
                    break;
                case -1:
                    if(var4 < 0 || var3 != null && var4 > var3.length - 1) {
                        throw new MissingFormatArgumentException(var8.toString());
                    }

                    var8.print(var3 == null?null:var3[var4], var1);
                    break;
                case 0:
                    ++var5;
                    var4 = var5;
                    if(var3 != null && var5 > var3.length - 1) {
                        throw new MissingFormatArgumentException(var8.toString());
                    }

                    var8.print(var3 == null?null:var3[var5], var1);
                    break;
                default:
                    var4 = var9 - 1;
                    if(var3 != null && var4 > var3.length - 1) {
                        throw new MissingFormatArgumentException(var8.toString());
                    }

                    var8.print(var3 == null?null:var3[var4], var1);
                }
            } catch (IOException var11) {
                this.lastException = var11;
            }
        }

        return this;
    }