有高手可否帮忙简化一段代码

Question

    C = Math.floor((A+B)/2);
    if (A > B) {
                            if (avg > C) {  
                                iPixel = 255;
                                //白色为0
                                mat[x][y] = 0;
                            } else {
                                column++;
                                iPixel = 0;
                                mat[x][y] = 1; //所有处理变0，1组成的为大矩阵
                            }
                        } else {
                            if (avg <= C) { //作为临界值100，128都可以，看效果//colorThreshold
                                iPixel = 255;
                                //白色为0
                                mat[x][y] = 0;
                            } else {
                                column++;
                                iPixel = 0;
                                mat[x][y] = 1; //所有处理变0，1组成的为大矩阵
                            }
                        }

此段代码冗余有点大，看着不够简单干净，一时也不好简化，本来想定义一个temp（if(A>B){temp ="avg>C";}else{temp ="avg<=C";}）存储avg与C的关系，作为if判断的参数，但是由于大小比较变换不能当作字符串处理。希望朋友能给点意见，谢谢！

Answer 1

C = Math.floor((A+B)/2);
if ((A > B && avg > C)||(A <= B && avg <= C)){
    iPixel = 255;
    //白色为0
    mat[x][y] = 0;
}else{
    column++;
    iPixel = 0;
    mat[x][y] = 1; //所有处理变0，1组成的为大矩阵
}

Answer 2

if((A > B && avg > C) || (A <= B && avg <= C)) { ... }

Answer 3

iPixel = 255;
mat[x][y] = 0;
C = (A+B) >> 1;
if (A > B && avg <= C || A <= B && avg > C) {
    column++;
    iPixel = 0;
    mat[x][y] = 1;
}

Answer 4

JS 的位运算并不比乘法除法快

if( (A>B)==(A+B<2*avg) ){
    iPixel = 255;
    mat[x][y] = 0;
}else{
    column++;
    iPixel = 0;
    mat[x][y] = 1;
}