Springmvc的controller返回的modelAndView（jsonSuccess）里面的地址根本不存在啊？

Question

@RequestMapping(value = "/add", method = RequestMethod.POST)
    public ModelAndView add(HttpServletRequest request,
            HttpServletResponse response, ZqbpCommonSerlect item) {
        ConnectionSource connectionSource = DBUtil.getConnectionSource();
        try {
            Dao<ZqbpCommonSerlect, String> dao = DaoManager.createDao(connectionSource,
                    ZqbpCommonSerlect.class);
            item.setSelectId(UUID.randomUUID().toString().replaceAll("-", ""));

            dao.create(item);
            connectionSource.close();
        } catch (SQLException e) {
            return jsonError(request, "保存失败", "");
        }
        return jsonSuccess(request, "保存成功！", getBasePath(request)+ "admin/chanpin/index.html");

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为什么还能正常打开？是不是这个地址并不是modelAndView数据所传递的地址？

Answer 1

看看你这个Controller是否有父类，有的话看看父类里是否有这个方法。。。用编辑器也可以直接跳转啊

Answer 2

当然是传给视图，这个modelandview对象就是controller处理后返回的赛