underscore.js 数组拆分

Question

//原数组

[
      {n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"在吗555",date:"2010-12-23"},
       {n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"回来了吗",date:"2019-12-23"}
      {n:"刘云",a:"static/images/ly.jpg",from:"10", to: "1",msg:"回来了:)",date:"2019-12-3"},
       {n:"刘云",a:"static/images/ly.jpg",from:"10", to: "1",msg:"给你带了东西",date:"2019-12-23"},
       {n:"刘云",a:"static/images/ly.jpg",from:'10', to: "1",msg:"累死了",date:"2012-1-1"}
 ]

拆分为这个样子

[ 


  [
      {n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"在吗555",date:"2010-12-23"},
       {n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"回来了吗",date:"2019-12-23"}
  ],


  [
      {n:"刘云",a:"static/images/ly.jpg",from:"10", to: "1",msg:"回来了:)",date:"2019-12-3"},
       {n:"刘云",a:"static/images/ly.jpg",from:"10", to: "1",msg:"给你带了东西",date:"2019-12-23"},
       {n:"刘云",a:"static/images/ly.jpg",from:'10', to: "1",msg:"累死了",date:"2012-1-1"}
  ],


]

如何用 underscore 实现

Answer 1

groupBy

Answer 2

为什么要用underscore呢？用原生写也很好实现吧。
1.循环得出唯一的人名数组
2.循环原数组，同名就push进去
3.重新组合

Answer 3

@小_秦 你真牛逼，看文档的学习能力太强了，羡慕：）