angularjs factory 返回数组前台ionic不显示

Question

刚接触ionic和angular：
.factory('Recos', function() {

var recos=
[
    {   
        recoid:0,
        cityname:"上海",
        cityintroduce:"",
        citytext:"",
        img:"",
    },
    {
        recoid:1,
        cityname:"北京",
        cityintroduce:"",
        citytext:"",
        img:"",
    },
    {
        recoid:2,
        cityname:"深圳",
        cityintroduce:"",
        citytext:"",
        img:"",
    },
    {
        recoid:3,
        cityname:"",
        cityintroduce:"",
        citytext:"”。",
        img:"",
    }
];

return {
allreco: function() {
        return recos; //标注
},
get: function(recoid) {
  for (var i = 0; i < recos.length; i++) {
    if (recos[i].recoid === parseInt(recoid)) {
      return recos[i];
    }
  };
},

};
})

"//标注"的地方这样是正常的，但是改成return recos[0]或者recos[1]...前台调用就不显示数据，这是为什么呢~;因为想做一个简单的匹配功能：

return {

allreco: function() {
  var city = localStorage.city;  
  for (var i = 0; i < recos.length; i++) {
      if (city.indexOf(recos[i].cityname) != -1){
        return recos[i];
      }
  };
},
get: function(recoid) {
  for (var i = 0; i < recos.length; i++) {
    if (recos[i].recoid === parseInt(recoid)) {
      return recos[i];
    }
  };
},

};

碰到了这个问题,不知道其中原因。

Answer 1

allreco的意思应该是返回所有的reco，为什么会变成return recos[i]，你是想返回所有在localStorage.city里面的reco吗？

allreco: function(){
    var city = localStorage.city;  
    var result=[]
      for (var i = 0; i < recos.length; i++) {
          if (city.indexOf(recos[i].cityname) != -1){
           result.push(recos[i]);
          }
      };
    return result;
}