关于jquery函数运行先后的问题

Question

var alert_message = $("...");;
$("body:first").after(alert_message.fadeIn(800).fadeOut(800));
alert_message.remove();

怎样写才能做到完成fadeout效果后才运行remove？

Answer 1

alert_message.fadeIn(800).fadeOut(800, function() {
    $(this).remove()
})

Answer 2

 alert_message.insertAfter("body").fadeIn(800).fadeOut(800, function() {
        $(this).remove()
    })