Python 取一个时间段里面的时间

Question

实现效果如下：如规定时间10:00:00~18:00:00 我想随机取里面的时间里面

Answer 1

提供个思路，不写代码了。你把这个时间段转换成总共的秒数。
定一个用秒数表示的start_time和end_time；
random（start_time，end_time）；
然后转换成时间呗。

Answer 2

import datetime 
import random

def random_datetime(start_datetime, end_datetime):
    delta = end_datetime - start_datetime
    inc = random.randrange(delta.total_seconds())
    return start_datetime + datetime.timedelta(seconds=inc)

if __name__=='__main__':
    start_datetime = datetime.datetime(2016, 8, 17, 10, 0, 0)
    end_datetime = datetime.datetime(2016, 8, 17, 18, 0, 0)
    dt = random_datetime(start_datetime, end_datetime)
    print(dt)

結果:

2016-08-17 11:59:04

---

我回答過的問題: Python-QA

Answer 3

from random import randint

"{}:{}:{}".format(randint(10,17),randint(0,59),randint(0,59))

Answer 4

楼上的是一种好思路，我再提供一个low一点的写法

from random import randint

h, m, s = randint(10, 18), 0, 0

if h != 18:
    m = randint(0, 59)
    s = randint(0, 59)

print '%d:%02d:%02d' % (h, m, s)

Answer 5

写了一个生成上班签到记录的。

#python生成随机时间段
#2016年12月6日18:34:26 codegay
#参考资料 http://www.runoob.com/python/python-date-time.html
#Python 取一个时间段里面的时间 https://segmentfault.com/q/1010000006617581

import time
import random
st = "2016-12-6 18:40:36"
et = "2016-12-16 18:40:44"
tf = "%Y-%m-%d %H:%M:%S"

name = """11
22
33
44
狗三
猫4
猪八"""
namelist = name.splitlines()
count = len(namelist)

print(namelist)

def random_time(st,et,count=1):
    start = int(time.mktime(time.strptime(st,tf)))
    end = int(time.mktime(time.strptime(et,tf)))
    mktime =  random.sample(range(start,end),count)
    strtime = [time.strftime(tf,time.localtime(r)) for r in sorted(mktime)]
    return strtime

result = random_time(st,et,count)

random.shuffle(namelist)#打乱名单的顺序

for t in zip(result,namelist):
    print(*t)


"""
输出:
['11', '22', '33', '44', '狗三', '猫4', '猪八']
2016-12-08 04:00:26 33
2016-12-09 11:16:06 猪八
2016-12-12 08:13:51 狗三
2016-12-12 11:57:52 猫4
2016-12-12 12:56:37 11
2016-12-12 22:20:52 44
2016-12-16 02:47:04 22
"""