make_celery 构造函数中的 abstract=True 的作用？

Question

代码: celery 构造函数，在celery中加载flask的app context:

def make_celery(app):
    celery = Celery(app.import_name, broker=app.config['CELERY_BROKER_URL'])
    celery.conf.update(app.config)
    TaskBase = celery.Task
    class ContextTask(TaskBase):
        abstract = True
        def __call__(self, *args, **kwargs):
            with app.app_context():
                return TaskBase.__call__(self, *args, **kwargs)
    celery.Task = ContextTask
    return celery

请问，这里的abstract=True的作用是? 谢谢各位!

Answer 1

建议直接看源码，一般源码中有注释：
celery/app/task.py:

#: If :const:`True` the task is an abstract base class.
abstract = True