JQ函数值传递问题

Question

 $('.seeMoreProduct').click(function(){
            var seeMoreIndexNum = ($('.seeMoreProduct').index($(this)));
        });
        var $newDesignSection = $('#designer_detail_con');
        if($(".designer_ul").length > 0) {
            $(".designer_ul").on("click",".ui_scroll_con > li",function(){
                var $this = $(this);
                $.ajax({
                    url: $this.attr('dataUrl'),
                    dataType: 'html',
                    success: function(data){
                        $newDesignSection.html(data);
                    }
                });

            }).find('.designer_List').eq(seeMoreIndexNum).click();
        } 

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希望能做获取到seeMoreIndexNum的值，('.designer_List').eq（seeMoreIndexNum）这里获取不到

Answer 1

seeMoreIndexNum是个匿名函数的内部变量，你定义一个，跟当前代码同级作用域的变量好了