如要处理以下markdown:
# I miss you
my name is Gina,
This is my cloum: [sdf
df](http://zhuanlan.zhihu.com/xxxzzz)
and this is my weibo:[sina blog](https://link.zhihu.com/?target=http%3A//weibo.com/u/2355944%3Fis_hot%3D1)
我写的代码:
from __future__ import unicode_literals, print_function
import re
content='''
# I miss you
my name is Gina,
This is my cloum: [sdf
df](http://zhuanlan.zhihu.com/xxxzzz)
and this is my weibo:[sina blog](https://link.zhihu.com/?target=http%3A//weibo.com/u/2355944%3Fis_hot%3D1)
'''
linklist = re.findall('\[(.+?)\]\((.+?)\)',content,re.S)
for link in linklist:
link[0].replace("\r\n","")
link[1].replace("\r\n","")
link[1].replace('https://ref.zhihu.com/?redrict=','')
print (content)
显而易见的。。以上代码不能运行。。如何得到我想要的:
# I miss you
my name is Gina,
This is my cloum: [sdfdf](http://zhuanlan.zhihu.com/xxxzzz)
and this is my weibo:[sina blog](http://weibo.com/u/2355944?is_hot=1)
呢?
找到以下教程:
https://segmentfault.com/q/10...
http://www.crifan.com/python_...
问题已解决
输出: