是这样的,我要在li中不停的轮换样式,求实现方法,我不知道怎么处理超过第4个时补到最前面的实现,求指点!
循环开始时 currentIndex = 0 (指针),itemLens = 4(数据条数)
1.第一次循环
if(currentIndex >= itemLens){
currentIndex = 0
}
<li class="li-01"></li>
<li class="li-02"></li>
<li class="li-03"></li>
<li class="li-04"></li>
currentIndex++
2.第二次循环
<li class="li-04"></li>
<li class="li-01"></li>
<li class="li-02"></li>
<li class="li-03"></li>
currentIndex++
3.第三次循环
<li class="li-03"></li>
<li class="li-04"></li>
<li class="li-01"></li>
<li class="li-02"></li>
currentIndex++
4.第三次循环
<li class="li-02"></li>
<li class="li-03"></li>
<li class="li-04"></li>
<li class="li-01"></li>
currentIndex++
补充一下框架代码
<pre>
<!doctype html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport"
content="width=device-width, user-scalable=no, initial-scale=1.0, maximum-scale=1.0, minimum-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Document</title>
</head>
<body>
<div class="farm-current">
<ul>
<li class="li-01"></li>
<li class="li-02"></li>
<li class="li-03"></li>
<li class="li-04"></li>
</ul>
</div>
<script src="http://apps.bdimg.com/libs/jquery/1.9.1/jquery.min.js"></script>
<script>
$(function(){
var timer = null;
var $items = $('.farm-current').find('li');
var itemsLens = $items.length;
var currentIndex = 0;
setInterval(function(){
move($items)
}, 1000);
function move($items){
for(var i = 0; i < itemsLens; i++){
if(currentIndex >= itemsLens){
currentIndex = 0
}
/*实现代码*/
currentIndex++;
}
}
})
</script>
</body>
</html>
</pre>
我水平不高,代码写的不好,但是我觉这应该是你要效果