正则表达式匹配获取指定内容

Question

有一个字符串

var str = '//@(test/js/index.js); //@(tass/js/inde.js); //@(tab/jsx/ind.jsx); 11230120 ;// var a = 22';';

我用 var reg = /(\/\/\@\()(\S*?)(\))/g ;
结果是这样的

有没有一个正则匹配的规则；能获取到这样的结果

['test/js/index.js','tass/js/inde.js','tab/jsx/ind.jsx]

Answer 1

/(?:@\()([^)]*)/g 测试地址

const regex = /(?:@\()([^)]*)/g;
const str = `//@(test/js/index.js); //@(tass/js/inde.js); //@(tab/jsx/ind.jsx); 11230120 ;// var a = 22';`;
let m;

while ((m = regex.exec(str)) !== null) {
    // This is necessary to avoid infinite loops with zero-width matches
    if (m.index === regex.lastIndex) {
        regex.lastIndex++;
    }
    
    // The result can be accessed through the `m`-variable.
    m.forEach((match, groupIndex) => {
        console.log(`Found match, group ${groupIndex}: ${match}`);
    });
}

Answer 2

const reg = /[a-z]+\/jsx?\/inde?x?\.js/g,
    str = '//@(test/js/index.js); //@(tass/js/inde.js); //@(tab/jsx/ind.jsx); 11230120 ;// var a = 22';
    
str.match(reg);

Answer 3

/\(([^)]+)/g

Answer 4