laravel make方法疑惑

Question

$concrete = $this->getConcrete($abstract);

这里获取接口对应的具体类即$concrete，只能是闭包或者$abstract == $concrete的情况吧。那么接下来的

if ($this->isBuildable($concrete, $abstract)) {
    $object = $this->build($concrete, $parameters);
} else {
    $object = $this->make($concrete, $parameters);
}

这里的else的make还有什么用呢？

Answer 1

我想应该是递归

$object = $this->make($concrete);

把$concrete作为$abstract寻找concrete

$abstract = $this->getAlias($abstract);