怎么用filter实现这种过滤

Question

let arr1 = ['a','b','c','d'];
let arr2 = [1,4];//通过这个数组过滤掉arr1中索引为1跟4的选项

能用filter实现么

Answer 1

let arr1 = ['a','b','c','d'];
let arr2 = [1,4];
arr1.filter((value,index)=>{
    return arr2.indexOf(index) === -1;
});

Answer 2

arr1.filter(function(){
       for(let i = 0 , i < arr2.length, i++){
              return arr1[arr2[i]] 
       }
})

Answer 3

let newArr = arr1.filter((el, index, array) => {
    return arr2.indexOf(index) === -1
})

let newArr = arr1.filter((el, index, array) => {
    return !arr2.includes(index)
})

Answer 4

arr1 = arr1.filter((e,i) => arr2.indexOf(i)===-1)
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