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1.针对一个文章,我有N多的评论
2.现在我想获取到每篇文章最新的评论
这个子查询是可以的 ,但是要求是不用子查询,如何实现呢
SELECT FROM (SELECT FROM old_chapter_check_list ORDER BY id DESC) AS t GROUP BY cid LIMIT 10

5个回答

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已采纳

按你的描述你的sql貌似并不满足呢
两种写法
1、一定不要子查询的,确认评论中不包含某种分隔符的话(比如“|||”)使用substring_index(group_concat))函数处理:

select substring_index(group_concat(comment_content order by id desc separator '|||'),'|||',1) cmt,cid from old_chapter_check_list group by cid limit 10;

2、不确定是否包含特殊字符的写法,先取出有最新评论的10个文章最新id值(唯一自增主键的话)再进行联表查询

select a.cid,a.comment_content from old_chapter_check_list a join (select max(id) maxid from old_chapter_check_list group by cid order by maxid desc limit 10) b on a.id=b.maxid;
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SELECT * FROM old_chapter_check_list GROUP BY cid ORDER BY id DESC LIMIT 10

使用多次查询

SELECT max(id) FROM old_chapter_check_list GROUP BY articleid

查询出每篇文件评论的最大id

根据前面的结果集,在循环中查询最大id对应的评论

select * from old_chapter_check_list where cid = maxid
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写个视图直接从视图里取

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学生表取各班级年龄较大的2名

1、select * from tb A where id in (select id from tb B where A.class = B.class order by age desc limit 2) 

2、select * from tb B where 2 > (select count(*) from tb B where A.class = B.class and B.age > A.age)

3、select A.id,A.name,A.age,A.class from group_by_test A left join group_by_test B on A.class = B.class and A.age < B.age group by A.name,A.age,A.class having count(B.age)<2
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这样就可以了,id自增,cid自增的情况

SELECT *,MAX(id) max_id FROM old_chapter_check_list GROUP BY cid order by max_id LIMIT 10

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