两个数组格式存在差异，对比去重的问题

Question

arr1 =[{"id":1,"a":2},{"id":2,"c":3},{"id":3,"d":3},{"id":4,"d":3}];
arr2 =[{"id":3,"ed":1111,"vvv":121},{"id":4,"fa":2222},{"id":5,"sa":2222}];

arr1和arr2数组格式是不一样的，但是arr2中的id3和id4却和arr1一样,
怎么实现两个数组对比后，发现ID重复了，删除arr1中id为3和id4的整个对象？

Answer 1

var result = arr1.filter(function(element1) {
   return !arr2.find(function(element2) { 
       return element2.id == element1.id;
   });
});
console.log(result);