webpack 排除编译文件夹报错。

Question

想要排除webpack的loader中，一些文件夹不需要处理：

 {
    test: /\.(png|jpe?g|gif|svg)(\?.*)?$/,
    loader: 'url',
    include: [path.resolve(__dirname, '../src/st')],
    exclude: [path.resolve(__dirname, '../src/st/img/ex')],
    query: {
      limit: 10000,
      name: utils.assetsPath('img/[name].[hash:7].[ext]')
    }
  },

编译报错：You may need an appropriate loader to handle this file type.

只要把：exclude: [path.resolve(__dirname, '../src/st/img/ex')],这个注销，就能够正常。请问怎样才能排除不需要编译的文件夹。

Answer 1

比如你不想编译node_modules，直接排除就可以了

  exclude: /node_modules/,