Scrapy中xpath用到中文报错

Question

问题描述

links = sel.xpath('//i[contains(@title,"置顶")]/following-sibling::a/@href').extract()

报错：ValueError: All strings must be XML compatible: Unicode or ASCII, no NULL bytes or control characters

Answer 1

参见文章：解决Scrapy中xpath用到中文报错问题

解决方法

方法一：将整个xpath语句转成Unicode

links = sel.xpath(u'//i[contains(@title,"置顶")]/following-sibling::a/@href').extract()

方法二：xpath语句用已转成Unicode的title变量

title = u"置顶"
links = sel.xpath('//i[contains(@title,"%s")]/following-sibling::a/@href' %(title)).extract()

方法三：直接用xpath中变量语法($符号加变量名)$title, 传参title即可

links = sel.xpath('//i[contains(@title,$title)]/following-sibling::a/@href', title="置顶").extract()

Answer 2

整个字符串前加个u试试