python3.5 urllib.request.urlopen报错

Question

小白想自学python爬取网页信息，但是代码写了第二行就老是报错，度娘了很久感觉不是很能get,求大神点拨！

import urllib.request

Target = "http://www.tmsf.com/newhouse/property_330181_287055905_price.htm"
url = urllib.request.urlopen(Target)-----报错行
page = url.read()
url.close()
fp = open("grab.txt","wb")
fp.write(page)
fp.close()

报错信息
Traceback (most recent call last):
File "C:UsersjqhDesktop1.py", line 35, in <module>

url = urllib.request.urlopen(Target)

File "C:UsersjqhAppDataLocalProgramsPythonPython35liburllibrequest.py", line 162, in urlopen

return opener.open(url, data, timeout)

File "C:UsersjqhAppDataLocalProgramsPythonPython35liburllibrequest.py", line 471, in open

response = meth(req, response)

File "C:UsersjqhAppDataLocalProgramsPythonPython35liburllibrequest.py", line 581, in http_response

'http', request, response, code, msg, hdrs)

File "C:UsersjqhAppDataLocalProgramsPythonPython35liburllibrequest.py", line 509, in error

return self._call_chain(*args)

File "C:UsersjqhAppDataLocalProgramsPythonPython35liburllibrequest.py", line 443, in _call_chain

result = func(*args)

File "C:UsersjqhAppDataLocalProgramsPythonPython35liburllibrequest.py", line 589, in http_error_default

raise HTTPError(req.full_url, code, msg, hdrs, fp)

urllib.error.HTTPError: HTTP Error 403: Forbidden

Answer 1

http 403 是对方网站返回的信息，你的代码没问题。

我用你的代码在python3.6.1下作了测试，可以正常运行，页面内容保存在grab.txt中。

Answer 2

这是你访问的链接返回403了啊，如何浏览器访问正常，可以加上cookie和header，然后再试试